Question a-circ

4.1 Lines, Angles, and Triangles - Triangle sum theorem
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A circle has center O , and points R and S lie on the circle. In triangle O R S , the measure of ROS is 88°. What is the measure of RSO, in degrees? (Disregard the degree symbol when entering your answer.)

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A circle has center O , and points R and S lie on the circle. In

Hard-difficulty · SAT Math · Lines, Angles, and Triangles — Triangle sum theorem. Read the question above, select your answer, and check the full explanation below to understand exactly why the correct choice works.

Answer explanation

The correct answer is 46 . It's given that O is the center of a circle and that points R and S lie on the circle. Therefore, OR/mo> and OS/mo> are radii of the circle. It follows that OR=OS. If two sides of a triangle are congruent, then the angles opposite them are congruent. It follows that the angles RSO and ORS, which are across from the sides of equal length, are congruent. Let x/mo> represent the measure of RSO. It follows that the measure of  ORS is also x/mo>. It's given that the measure of  ROS is 88/mo>. Because the sum of the measures of the interior angles of a triangle is 180/mo>, the equation x/mo>+x/mo>+88/mo>=180/mo>, or 2x+88=180, can be used to find the measure of RSO. Subtracting 88  from both sides of this equation yields 2x=92. Dividing both sides of this equation by 2 yields x=46. Therefore, the measure of RSO, in degrees, is 46 .

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