Question for-th

1.1 Linear Functions - Graphs in slope-intercept, point-slope, standard form
0:00

For the function f , the graph of y=f(x) in the xy-plane has a slope of 3 and passes through the point 0,-8. Which equation defines f ?

A.

f(x)=3x

B.

f(x)=3x-8

C.

f(x)=3x+5

D.

f(x)=3x+11

For the function f , the graph of y = f ( x ) in the

Medium-difficulty · SAT Math · Linear Functions — Graphs in slope-intercept, point-slope, standard form. Read the question above, select your answer, and check the full explanation below to understand exactly why the correct choice works.

Answer explanation

Choice B is correct. An equation defining a linear function can be written in the form fx=mx+b, where m and b are constants, m is the slope of the graph of y=fx in the xy-plane, and 0,b is the y-intercept of the graph. It's given that for the function f , the graph of y=fx in the xy-plane has a slope of 3 . Therefore, m=3. It's also given that this graph passes through the point 0,-8. Therefore, the y-intercept of the graph is 0,-8, and it follows that b=-8. Substituting 3 for m and -8 for b in the equation fx=mx+b yields fx=3x-8. Thus, the equation that defines f is fx=3x-8.

Choice A is incorrect. For this function, the graph of y=fx in the xy-plane passes through the point 0,0, not 0,-8.

Choice C is incorrect. For this function, the graph of y=fx in the xy-plane passes through the point 0,5, not 0,-8.

Choice D is incorrect. For this function, the graph of y=fx in the xy-plane passes through the point 0,11, not 0,-8.