Question in-the

1.1 Linear Functions - Parallel/perpendicular line relationships
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In the xy-plane, line k is defined by x plus y equals 0. Line j is perpendicular to line k, and the y-intercept of line j is the point with coordinates 0 comma 3. Which of the following is an equation of line j ?

A.

x plus y, equals 3

B.

x plus y, equals negative 3

C.

x minus y, equals 3

D.

x minus y, equals negative 3

In the xy -plane, line k is defined by . Line j is perpendicular to line

Hard-difficulty · SAT Math · Linear Functions — Parallel/perpendicular line relationships. Read the question above, select your answer, and check the full explanation below to understand exactly why the correct choice works.

Answer explanation

Choice D is correct. It’s given that line j is perpendicular to line k and that line k is defined by the equation x plus y, equals 0. This equation can be rewritten in slope-intercept form, y equals, m x plus b, where m represents the slope of the line and b represents the y-coordinate of the y-intercept of the line, by subtracting x from both sides of the equation, which yields y equals, negative x. Thus, the slope of line k is negative 1. Since line j and line k are perpendicular, their slopes are opposite reciprocals of each other. Thus, the slope of line j is 1. It’s given that the y-intercept of line j is the point with coordinates 0 comma 3. Therefore, the equation for line j in slope-intercept form is y equals, x plus 3, which can be rewritten as x minus y, equals negative 3.

Choices A, B, and C are incorrect and may result from conceptual or calculation errors.