Question in-the

2.3 Systems Involving Nonlinear Equations - Line + parabola intersections
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In the xy-plane, the graph of the equation y = - x 2 + 9 x - 100 intersects the line y = c at exactly one point. What is the value of c ?

A.

- 9 2

B.

- 319 4

C.

- 481 4

D.

-100

In the xy -plane, the graph of the equation y = - x 2 + 9

Hard-difficulty · SAT Math · Systems Involving Nonlinear Equations — Line + parabola intersections. Read the question above, select your answer, and check the full explanation below to understand exactly why the correct choice works.

Answer explanation

Choice C is correct. In the xy-plane, the graph of the line y=c is a horizontal line that crosses the y-axis at y=c and the graph of the quadratic equation y=-x2+9x-100 is a parabola. A parabola can intersect a horizontal line at exactly one point only at its vertex. Therefore, the value of c should be equal to the y-coordinate of the vertex of the graph of the given equation. For a quadratic equation in vertex form, y=ax-h2+k, the vertex of its graph in the xy-plane is h,k. The given quadratic equation, y=-x2+9x-100, can be rewritten as y=-x2-292x+922+922-100, or y=-x-922+-3194. Thus, the value of c is equal to -3194.

Choice A is incorrect and may result from conceptual or calculation errors.

Choice B is incorrect and may result from conceptual or calculation errors.

Choice D is incorrect and may result from conceptual or calculation errors.