Line k is defined by y = 1 4 x + 1 . Line j is parallel to line k

Question

Line k is defined by y = 1 4 x + 1 . Line j is parallel to line k in the xy -plane. What is the slope of j ?

Accepted Answer

The correct answer is 1 4 . It's given that line k is defined by y = 1 4 x + 1 . It's also given that line j is parallel to line k in the xy -plane. A line in the xy -plane represented by an equation in slope-intercept form y = m x + b has a slope of m and a y -intercept of 0 , b . Therefore, the slope of line k is 1 4 . Since parallel lines have equal slopes, the slope of line j is 1 4 . Note that 1/4 and .25 are examples of ways to enter a correct answer.

Question line-k