Question moving

1.3 Linear Equations in Two Variables - Intercepts and slope applications
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  • Moving from left to right:
    • The curve passes from quadrant 3 to quadrant 4.
    • In quadrant 3, the curve trends up sharply to point (0 comma negative 6).
    • In quadrant 4, the curve trends up gradually.
  • As x increases, the curve approaches the line y equals negative 5.
  • The curve passes through the following points:
    • (0 comma negative 6)
    • (1 comma negative 5 and one sixth)

What is the y-intercept of the graph shown?

A.

0,-6

B.

-6,0

C.

0,0

D.

-5,-5

Moving from left to right: The curve passes from quadrant 3 to quadrant 4. In quadrant

Easy-difficulty · SAT Math · Linear Equations in Two Variables — Intercepts and slope applications. Read the question above, select your answer, and check the full explanation below to understand exactly why the correct choice works.

Answer explanation

Choice A is correct. The y-intercept of a graph in the xy-plane is the point x,y on the graph where x = 0 . For the graph shown, at x = 0 , the corresponding value of y is -6 . Therefore, the y-intercept of the graph shown is 0,-6.

Choice B is incorrect and may result from conceptual errors.

Choice C is incorrect and may result from conceptual errors.

Choice D is incorrect and may result from conceptual errors.