Question the-pa

2.1 Nonlinear Functions - Quadratic graphs and vertex form
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  • The parabola opens downward.
  • The vertex is at point (4 comma 9).
  • The parabola passes through the following points:
    • (0 comma 5)
    • (2 comma 8)
    • (4 comma 9)
    • (6 comma 8)

The graph models the number of active projects a company was working on x months after the end of November 2012 , where 0x6. According to the model, what is the predicted number of active projects the company was working on at the end of November 2012 ?

A.

0

B.

5

C.

8

D.

9

The parabola opens downward. The vertex is at point (4 comma 9). The parabola passes through

Hard-difficulty · SAT Math · Nonlinear Functions — Quadratic graphs and vertex form. Read the question above, select your answer, and check the full explanation below to understand exactly why the correct choice works.

Answer explanation

Choice B is correct. It's given that the graph models the number of active projects a company was working on x months after the end of November 2012. Therefore, the value of x that corresponds to the end of November 2012 is 0 . The point at which x = 0 is the y-intercept of the graph. It follows that the y-intercept of the graph shown is the point 0,5. Therefore, according to the model, the predicted number of active projects the company was working on at the end of November 2012 is 5 .

Choice A is incorrect. This is the value of x that corresponds to the end of November 2012, not the predicted number of active projects the company was working on at the end of November 2012.

Choice C is incorrect. This is the predicted number of active projects the company was working on 2 months after the end of November 2012.

Choice D is incorrect. This is the predicted number of active projects the company was working on 4 months after the end of November 2012.