y = 12 x - 20 y = 28 What is the solution x , y

Choice A is correct. The second equation in the given system is $y=28$. Substituting $28$ for $y$ in the first equation in the given system yields $28=12x-20$. Adding $20$ to both sides of this equation yields $48=12x$. Dividing both sides of this equation by $12$ yields $4=x$. Therefore, the solution $\left(x,y\right)$ to the given system of equations is $\left(4,28\right)$.

Choice B is incorrect and may result from conceptual or calculation errors.

Choice C is incorrect. This is the solution $\left(y,x\right)$, not $\left(x,y\right)$, to the given system of equations.

Choice D is incorrect and may result from conceptual or calculation errors.