Question y-8804

5.1 Linear Inequalities in One or Two Variables - Systems of inequalities and feasible region
0:00

yx+7

y-2x-1

Which point x,y is a solution to the given system of inequalities in the xy-plane?

A.

-14,0

B.

0,-14

C.

0,14

D.

14,0

y ≤ x + 7 y ≥ - 2 x - 1 Which point x ,

Hard-difficulty · SAT Math · Linear Inequalities in One or Two Variables — Systems of inequalities and feasible region. Read the question above, select your answer, and check the full explanation below to understand exactly why the correct choice works.

Answer explanation

Choice D is correct. A point x,y is a solution to a system of inequalities in the xy-plane if substituting the x-coordinate and the y-coordinate of the point for x and y , respectively, in each inequality makes both of the inequalities true. Substituting the x-coordinate and the y-coordinate of choice D, 14 and 0 , for x and y , respectively, in the first inequality in the given system, ydx+7, yields 0d14+7, or 0d21, which is true. Substituting 14 for x and 0 for y in the second inequality in the given system, ye-2x-1, yields 0e-214-1, or 0e-29, which is true. Therefore, the point 14,0 is a solution to the given system of inequalities in the xy-plane.

Choice A is incorrect. Substituting -14 for x and 0 for y in the inequality ydx+7 yields 0d-14+7, or 0d-7, which is not true.

Choice B is incorrect. Substituting 0 for x and -14 for y in the inequality ye-2x-1 yields -14e-20-1, or -14e-1, which is not true.

Choice C is incorrect. Substituting 0 for x and 14 for y in the inequality ydx+7 yields 14d0+7, or 14d7, which is not true.