y = x 2 + 14 x + 48 x + 8 = 11 The solution

The correct answer is $99$. In the given system of equations, the second equation is $x+8=11$. Subtracting $8$ from both sides of this equation yields $x=3$. In the given system of equations, the first equation is $y=x^2+14x+48$. Substituting $3$ for $x$ in this equation yields $y={\left(3\right)}^2+14\left(3\right)+48$, or $y=99$. Therefore, the solution to the given system of equations is $\left(x,y\right)=\left(3,99\right)$. Thus, the value of $y$ is $99$.