In 2008 , Zinah earned 14 % more than in 2007 , and in 2009 Zinah

Choice D is correct. It’s given that in $2008$ Zinah earned $14\%$ more than in $2007$. Let $h$ represent the amount Zinah earned in $2007$ and let $j$ represent the amount that Zinah earned in $2008$. This situation can be represented by the equation $j=\left(1+\frac{14}{100}\right)h$, or $j=1.14h$. It’s also given that in $2009$ Zinah earned $4\%$ more than in $2008$. Let $k$ represent the amount Zinah earned in $2009$. This situation can be represented by the equation $k=\left(1+\frac{4}{100}\right)j$, or $k=1.04j$. Substituting $1.14h$ for $j$ in the equation $k=1.04j$ yields $k=\left(1.04\right)\left(1.14h\right)$, or $k=1.1856h$. If Zinah earned $y$ times as much in $2009$ as in $2007$, then the value of $y$ is $1.1856$.

Choice A is incorrect and may result from conceptual or calculation errors.

Choice B is incorrect and may result from conceptual or calculation errors.

Choice C is incorrect and may result from conceptual or calculation errors.