Question the-bo

5.1 Linear Inequalities in One or Two Variables - Graphing two-variable inequalities
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  • The boundary of the inequality is a dashed line.
    • The line slants sharply down from left to right.
    • The line passes through the following points:
      • (negative 1 comma 5)
      • (0 comma 1)
      • (1 comma negative 3)
  • The area above and to the right of the boundary is shaded.

The shaded region shown represents the solutions to which inequality?

A.

y<1+4x

B.

y<1-4x

C.

y>1+4x

D.

y>1-4x

The boundary of the inequality is a dashed line. The line slants sharply down from left

Hard-difficulty · SAT Math · Linear Inequalities in One or Two Variables — Graphing two-variable inequalities. Read the question above, select your answer, and check the full explanation below to understand exactly why the correct choice works.

Answer explanation

Choice D is correct. The equation for the line representing the boundary of the shaded region can be written in slope-intercept form y=b+mx, where m is the slope and 0,b is the y-intercept of the line. For the graph shown, the boundary line passes through the points 0,1 and 1,-3. Given two points on a line, x1,y1 and x2,y2, the slope of the line can be calculated using the equation m=y2-y1x2-x1. Substituting the points 0,1 and 1,-3 for x1,y1 and x2,y2 in this equation yields m=-3-11-0, which is equivalent to m=-41, or m=-4. Since the point 0,1 represents the y-intercept, it follows that b = 1 . Substituting -4 for m and 1 for b in the equation y=b+mx yields y=1-4x as the equation of the boundary line. Since the shaded region represents all the points above this boundary line, it follows that the shaded region shown represents the solutions to the inequality y>1-4x.

Choice A is incorrect. This inequality represents a region below, not above, a boundary line with a slope of 4 , not -4 .

Choice B is incorrect. This inequality represents a region below, not above, the boundary line shown.

Choice C is incorrect. This inequality represents a region whose boundary line has a slope of 4 , not -4 .