Question the-eq

3.1 Ratios, Rates, and Proportional Relationships - Direct/inverse proportionality
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d equals, 55 t

The equation above can be used to calculate the distance d, in miles, traveled by a car moving at a speed of 55 miles per hour over a period of t hours. For any positive constant k, the distance the car would have traveled after 9 k hours is how many times the distance the car would have traveled after 3 k hours?

A.

3

B.

6

C.

3k

D.

6 k

The equation above can be used to calculate the distance d , in miles, traveled by

Hard-difficulty · SAT Math · Ratios, Rates, and Proportional Relationships — Direct/inverse proportionality. Read the question above, select your answer, and check the full explanation below to understand exactly why the correct choice works.

Answer explanation

Choice A is correct. Since the distance is equal to the amount of time multiplied by a constant, the given equation d equals 55 t represents a proportional relationship between distance and time in this situation. Since 9 k equals, 3 times 3 k, the time when t equals 9 k hours is 3 times the time when t equals 3 k hours. Therefore, the distance traveled after 9 k hours is 3 times the distance after 3 k hours.

Choices B and D are incorrect and may result from interpreting the proportional relationship between time and distance as additive rather than multipliive. Choice C is incorrect and may result from an arithmetic error.