Question the-fo

5.1 Linear Inequalities in One or Two Variables - Solving single-variable inequalities
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we equals, V over R

The formula above is Ohm’s law for an electric circuit with current I, in amperes, potential difference V, in volts, and resistance R, in ohms. A circuit has a resistance of 500 ohms, and its potential difference will be generated by n six-volt batteries that produce a total potential difference of 6 n volts. If the circuit is to have a current of no more than 0.25 ampere, what is the greatest number, n, of six-volt batteries that can be used?

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The formula above is Ohm’s law for an electric circuit with current I , in amperes,

Hard-difficulty · SAT Math · Linear Inequalities in One or Two Variables — Solving single-variable inequalities. Read the question above, select your answer, and check the full explanation below to understand exactly why the correct choice works.

Answer explanation

The correct answer is 20. For the given circuit, the resistance R is 500 ohms, and the total potential difference V generated by n batteries is 6 n volts. It’s also given that the circuit is to have a current of no more than 0.25 ampere, which can be expressed as we is less than 0 point 2 5. Since Ohm’s law says that we equals, V over R, the given values for V and R can be substituted for I in this inequality, which yields 6 n over 500 is less than 0 point 2 5. Multiplying both sides of this inequality by 500 yields 6 n is less than 125, and dividing both sides of this inequality by 6 yields n is less than 20 point 8 3 3. Since the number of batteries must be a whole number less than 20.833, the greatest number of batteries that can be used in this circuit is 20.