The number a is 110 % greater than the number b . The number b is

The correct answer is $9.87$. It’s given that the number $a$ is $110\%$ greater than the number $b$. It follows that $a=\left(1+\frac{110}{100}\right)b$, or $a=2.1b$. It’s also given that the number $b$ is $90\%$ less than $47$. It follows that $b=\left(1-\frac{90}{100}\right)\left(47\right)$, or $b=0.1\left(47\right)$, which yields $b=4.7$. Substituting $4.7$ for $b$ in the equation $a=2.1b$ yields $a=2.1\left(4.7\right)$, which is equivalent to $a=9.87$. Therefore, the value of $a$ is $9.87$.