y > 4 x + 8 For which of the following tables are all the values of x and their

Question

y &#62; 4 x + 8 For which of the following tables are all the values of x and their corresponding values of y solutions to the given inequality?

Accepted Answer

Choice A is correct. In each choice, the values of x are 2 , 4 , and 6 . Substituting the first value of x , 2 , for x in the given inequality yields y &#62; 4 2 + 8 , or y &#62; 16 . Therefore, when x = 2 , the corresponding value of y must be greater than 16 . Of the given choices, only choice A is a table where the value of y corresponding to x = 2 is greater than 16 . To confirm that the other values of x in this table and their corresponding values of y are also solutions to the given inequality, the values of x and y in the table can be substituted for x and y in the given inequality. Substituting 4 for x and 30 for y in the given inequality yields 30 &#62; 4 4 + 8 , or 30 &#62; 24 , which is true. Substituting 6 for x and 41 for y in the given inequality yields 41 &#62; 4 6 + 8 , or 41 &#62; 32 , which is true. It follows that for choice A, all the values of x and their corresponding values of y are solutions to the given inequality. Choice B is incorrect. Substituting 2 for x and 8 for y in the given inequality yields 8 &#62; 4 2 + 8 , or 8 &#62; 16 , which is false. Choice C is incorrect. Substituting 2 for x and 13 for y in the given inequality yields 13 &#62; 4 2 + 8 , or 13 &#62; 16 , which is false. Choice D is incorrect. Substituting 2 for x and 13 for y in the given inequality yields 13 &#62; 4 2 + 8 , or 13 &#62; 16 , which is false.

$x$	$y$
$2$	$19$
$4$	$30$
$6$	$41$

$x$	$y$
$2$	$8$
$4$	$16$
$6$	$24$

$x$	$y$
$2$	$13$
$4$	$18$
$6$	$23$

$x$	$y$
$2$	$13$
$4$	$21$
$6$	$29$

Question y-62-4