A rectangle has a length of 64 inches and a width of 32 inches. What is

The correct answer is $\mathrm{2,048}$. The area $A$, in square inches, of a rectangle is equal to the product of its length $\mathcal{l}$, in inches, and its width $w$, in inches, or $A=\mathcal{l}w$. It's given that the rectangle has a length of $64$ inches and a width of $32$ inches. Substituting $64$ for $\mathcal{l}$ and $32$ for $w$ in the equation $A=\mathcal{l}w$ yields $A=\left(64\right)\left(32\right)$, or $A=\mathrm{2,048}$. Therefore, the area, in square inches, of the rectangle is $\mathrm{2,048}$.