Question moving

1.3 Linear Equations in Two Variables - Intercepts and slope applications
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  • Moving from left to right:
    • The curve passes from quadrant 3 to quadrant 4.
    • In quadrant 3, the curve trends up sharply to point (0 comma negative 5).
    • In quadrant 4, the curve trends up gradually.
  • As x increases, the curve approaches the line y equals negative 4.
  • The curve passes through the following points:
    • (negative 1 comma negative 9)
    • (0 comma negative 5)
    • (1 comma negative 4.2)

What is the y -intercept of the graph shown?

A.

-1,-9

B.

0,-5

C.

0,-4

D.

0,0

Moving from left to right: The curve passes from quadrant 3 to quadrant 4. In quadrant

Easy-difficulty · SAT Math · Linear Equations in Two Variables — Intercepts and slope applications. Read the question above, select your answer, and check the full explanation below to understand exactly why the correct choice works.

Answer explanation

Choice B is correct. The y-intercept of a graph in the xy-plane is the point x,y on the graph where x = 0 . At x = 0 , the corresponding value of y is -5 . Therefore, the y-intercept of the graph shown is 0,-5.

Choice A is incorrect and may result from conceptual errors.

Choice C is incorrect. This is the y-intercept of a graph in the xy-plane that intersects the y-axis at y = -4 , not y = -5 .

Choice D is incorrect. This is the y-intercept of a graph in the xy-plane that intersects the y-axis at y = 0 , not y = -5 .