Question to-ear
To earn money for college, Avery works two part-time jobs: A and B. She earns $10 per hour working at job A and $20 per hour working at job B. In one week, Avery earned a total of s dollars for working at the two part-time jobs. The graph above represents all possible combinations of numbers of hours Avery could have worked at the two jobs to earn s dollars. What is the value of s ?
128
160
200
320
To earn money for college, Avery works two part-time jobs: A and B. She earns $10
Hard-difficulty · SAT Math · Linear Equations in Two Variables — Intercepts and slope applications. Read the question above, select your answer, and check the full explanation below to understand exactly why the correct choice works.
Answer explanation
Choice B is correct. Avery earns $10 per hour working at job A. Therefore, if she works a hours at job A, she will earn dollars. Avery earns $20 per hour working at job B. Therefore, if she works b hours at job B, she will earn
dollars. The graph shown represents all possible combinations of the number of hours Avery could have worked at the two jobs to earn s dollars. Therefore, if she worked a hours at job A, worked b hours at job B, and earned s dollars from both jobs, the following equation represents the graph:
, where s is a constant. Identifying any point
from the graph and substituting the values of the coordinates for a and b, respectively, in this equation yield the value of s. For example, the point
, where
and
, lies on the graph. Substituting 16 for a and 0 for b in the equation
yields
, or
. Similarly, the point
, where
and
, lies on the graph. Substituting 0 for a and 8 for b in the equation
yields
, or
.
Choices A, C, and D are incorrect. If the value of s is 128, 200, or 320, then no points on the graph will satisfy this equation. For example, if the value of s is 128 (choice A), then the equation
becomes
. The point
, where
and
, lies on the graph. However, substituting 16 for a and 0 for b in
yields
, or
, which is false. Therefore,
doesn’t satisfy the equation, and so the value of s can’t be 128. Similarly, if
(choice C) or
(choice D), then substituting 16 for a and 0 for b yields
and
, respectively, which are both false.
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