Question 4-x-2-
What is the positive solution to the given equation?
- 4 x 2 - 7 x = - 36 What is the positive solution to
Hard-difficulty · SAT Math · Nonlinear Equations in One Variable — Quadratic solving (factoring, quadratic formula, completing square). Read the question above, select your answer, and check the full explanation below to understand exactly why the correct choice works.
Answer explanation
Choice B is correct. Multiplying each side of the given equation by yields . To complete the square, adding to each side of this equation yields , or . Taking the square root of each side of this equation yields two equations: and . Subtracting from each side of the equation yields . Dividing each side of this equation by yields , or . Therefore, is a solution to the given equation. Subtracting from each side of the equation yields . Dividing each side of this equation by yields . Therefore, the given equation has two solutions, and . Since is positive, it follows that is the positive solution to the given equation.
Alternate approach: Adding and to each side of the given equation yields . The right-hand side of this equation can be rewritten as . Factoring out the common factor of from the first two terms of this expression and the common factor of from the second two terms yields . Factoring out the common factor of from these two terms yields the expression . Since this expression is equal to , it follows that either or . Adding to each side of the equation yields . Dividing each side of this equation by yields . Therefore, is a positive solution to the given equation. Subtracting from each side of the equation yields . Therefore, the given equation has two solutions, and . Since is positive, it follows that is the positive solution to the given equation.
Choice A is incorrect. Substituting for in the given equation yields , which is false.
Choice C is incorrect. Substituting for in the given equation yields , which is false.
Choice D is incorrect. Substituting for in the given equation yields , which is false.
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