7 x 2 - 20 x - 32 = 0 What is the positive solution to

The correct answer is $4$. The left-hand side of the given equation can be factored as $\left(7x+8\right)\left(x-4\right)$. Therefore, the given equation, $7x^2-20x-32=0$, can be written as $\left(7x+8\right)\left(x-4\right)=0$. Applying the zero product property to this equation yields $7x+8=0$ and $x-4=0$. Subtracting $8$ from both sides of the equation $7x+8=0$ yields $7x=-8$. Dividing both sides of this equation by $7$ yields $x=-\frac{8}{7}$. Adding $4$ to both sides of the equation $x-4=0$ yields $x=4$. Therefore, the two solutions to the given equation, $7x^2-20x-32=0$, are $-\frac{8}{7}$ and $4$. It follows that $4$ is the positive solution to the given equation.