Question if-wha

2.2 Nonlinear Equations in One Variable - Quadratic solving (factoring, quadratic formula, completing square)
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If u minus 3 equals, the fraction 6 over, t minus 2, end fraction , what is t in terms of u ?

A.

t equals, the fraction 1 over u

B.

t equals, the fraction 2 u plus 9, over u

C.

t equals, the fraction 1 over, u minus 3, end fraction

D.

t equals, the fraction 2 u, over u minus 3, end fraction

If , what is t in terms of u ?

Hard-difficulty · SAT Math · Nonlinear Equations in One Variable — Quadratic solving (factoring, quadratic formula, completing square). Read the question above, select your answer, and check the full explanation below to understand exactly why the correct choice works.

Answer explanation

Choice D is correct. Multiplying both sides of the given equation by t minus 2 yields open parenthesis, t minus 2, close parenthesis, times, open parenthesis, u minus 3, close parenthesis, equals 6. Dividing both sides of this equation by u minus 3 yields t minus 2, equals, the fraction with numerator 6, and denominator u minus 3, end fraction. Adding 2 to both sides of this equation yields t equals, the fraction with numerator 6, and denominator u minus 3, end fraction, plus 2, which can be rewritten as t equals, the fraction with numerator 6, and denominator u minus 3, end fraction, plus, the fraction with numerator 2 times, open parenthesis, u minus 3, close parenthesis, and denominator u minus 3, end fraction. Since the fractions on the right-hand side of this equation have a common denominator, adding the fractions yields t equals, the fraction with numerator 6 plus 2, times, open parenthesis, u minus 3, close parenthesis, and denominator u minus 3, end fraction. Applying the distributive property to the numerator on the right-hand side of this equation yields t equals, the fraction with numerator 6 plus 2 u, minus 6, and denominator u minus 3, end fraction, which is equivalent to t equals, the fraction with numerator 2 u, and denominator u minus 3, end fraction.

Choices A, B, and C are incorrect and may result from various misconceptions or miscalculations.